To determine the quantum numbers for the valence electron of Rubidium (Rb, Z=37):

1. Electronic Configuration: Rubidium is an alkali metal located in Group 1 and Period 5 of the periodic table. Its electronic configuration corresponds to the noble gas Krypton (Z=36) followed by one electron in the next shell.

• Configuration: $[Kr] 5s^1$

2. Identify Quantum Numbers for the 5s electron:

• Principal Quantum Number (n): The electron is in the 5th shell, so $n = 5$.
• Azimuthal Quantum Number (l): The electron is in an 's' subshell. For s-orbitals, $l = 0$.
• Magnetic Quantum Number (m): The value of $m$ ranges from $-l$ to $+l$. Since $l = 0$, $m = 0$.
• Spin Quantum Number (s): Can be $+1/2$ or $-1/2$. The option $+1/2$ is standard.

3. Conclusion: The set is $5, 0, 0, +1/2$.