Which of the following is produced when anisole reacts with HI?
A
Benzaldehyde and ethanol
B
Acetophenone
C
Iodobenzene and methanol
D
Phenol and methyl iodide
Step-by-Step Solution
Reactants: Anisole is methyl phenyl ether (C6H5−O−CH3). HI is Hydrogen Iodide.
Mechanism: The reaction involves the cleavage of the ether linkage. In alkyl aryl ethers, the oxygen atom is attached to a benzene ring. The lone pair on the oxygen enters into resonance with the benzene ring, imparting a partial double bond character to the Cphenyl−O bond. This makes the Cphenyl−O bond much stronger and difficult to break compared to the Cmethyl−O bond.
Cleavage: Consequently, the weaker O−CH3 bond breaks. The proton (H+) from HI protonates the oxygen.
Nucleophilic Attack: The iodide ion (I−) attacks the smaller alkyl group (methyl group) via an SN2 mechanism.
Products: This results in the formation of Phenol (C6H5OH) and Methyl Iodide (CH3I).
Conclusion: The products are Phenol and methyl iodide.
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