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NEET CHEMISTRYMedium

Which of the following is produced when anisole reacts with HI?

A

Benzaldehyde and ethanol

B

Acetophenone

C

Iodobenzene and methanol

D

Phenol and methyl iodide

Step-by-Step Solution

  1. Reactants: Anisole is methyl phenyl ether (C6H5OCH3C_6H_5-O-CH_3). HI is Hydrogen Iodide.
  2. Mechanism: The reaction involves the cleavage of the ether linkage. In alkyl aryl ethers, the oxygen atom is attached to a benzene ring. The lone pair on the oxygen enters into resonance with the benzene ring, imparting a partial double bond character to the CphenylOC_{phenyl}-O bond. This makes the CphenylOC_{phenyl}-O bond much stronger and difficult to break compared to the CmethylOC_{methyl}-O bond.
  3. Cleavage: Consequently, the weaker OCH3O-CH_3 bond breaks. The proton (H+H^+) from HI protonates the oxygen.
  4. Nucleophilic Attack: The iodide ion (II^-) attacks the smaller alkyl group (methyl group) via an SN2S_N2 mechanism.
  5. Products: This results in the formation of Phenol (C6H5OHC_6H_5OH) and Methyl Iodide (CH3ICH_3I).
  6. Conclusion: The products are Phenol and methyl iodide.
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