Solved: CHEMISTRY Question for NEET

NEET CHEMISTRYMedium

4d, 5p, 5f and 6p orbitals are arranged in the order of decreasing energy. The correct option is

$5f > 6p > 5p > 4d$

$6p > 5f > 5p > 4d$

$6p > 5f > 4d > 5p$

$5f > 6p > 4d > 5p$

Step-by-Step Solution

Using the $(n + l)$ rule: For 4d, $n=4, l=2, n+l=6$ . For 5p, $n=5, l=1, n+l=6$ . For 5f, $n=5, l=3, n+l=8$ . For 6p, $n=6, l=1, n+l=7$ . Comparing $(n+l)$ values: $5f(8) > 6p(7) > 4d(6) = 5p(6)$ . Since 4d and 5p have the same $(n+l)$ , the one with higher $n$ has higher energy, so $5p > 4d$ . Thus, the order is $5f > 6p > 5p > 4d$ .

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started