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NEET CHEMISTRYMedium

What is the correct order of boiling points for the following compounds, arranged from the highest to the lowest? (a) Heptane (b) Butane (c) 2-Methylbutane (d) 2-Methylpropane (e) Hexane

A

(a) > (c) > (e) > (d) > (b)

B

(c) > (d) > (a) > (e) > (b)

C

(a) > (e) > (b) > (c) > (d)

D

(a) > (e) > (c) > (b) > (d)

Step-by-Step Solution

The boiling point of alkanes increases with an increase in molecular mass (number of carbon atoms) due to stronger van der Waals forces . For isomeric alkanes, the boiling point decreases with an increase in branching because the molecule becomes more spherical, reducing the surface area of contact and the magnitude of intermolecular forces .

Therefore, the order of boiling points based on the number of carbon atoms and branching is:

  1. Heptane (7 carbons)
  2. Hexane (6 carbons)
  3. 2-Methylbutane (5 carbons)
  4. Butane (4 carbons, unbranched)
  5. 2-Methylpropane (4 carbons, branched).

This corresponds to the sequence (a) > (e) > (c) > (b) > (d).

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