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NEET CHEMISTRYEasy

Standard electrode potential of three metals X, Y and Z are 1.2 V-1.2 \text{ V}, +0.5 V+0.5 \text{ V} and 3.0 V-3.0 \text{ V} respectively. The reducing power of these metals will be:

A

Y > X > Z

B

Z > X > Y

C

X > Y > Z

D

Y > Z > X

Step-by-Step Solution

The standard reduction potential is a measure of the tendency of a chemical species to get reduced. A more negative standard reduction potential indicates a greater tendency to undergo oxidation, which means it acts as a stronger reducing agent. Given standard reduction potentials are: EX=1.2 VE^\circ_{\text{X}} = -1.2 \text{ V} EY=+0.5 VE^\circ_{\text{Y}} = +0.5 \text{ V} EZ=3.0 VE^\circ_{\text{Z}} = -3.0 \text{ V} As the value of standard reduction potential decreases, the reducing power increases. The order of standard reduction potential is: EZ<EX<EYE^\circ_{\text{Z}} < E^\circ_{\text{X}} < E^\circ_{\text{Y}}. Therefore, the order of reducing power of the given metals is: Z>X>Y\text{Z} > \text{X} > \text{Y}.

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