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NEET CHEMISTRYMedium

Match List-I with List-II:

List-I (Amines) (a) N-Methylmethanamine (b) Ammonia (c) N-Methylaniline (d) Benzenamine

List-II (pKbpK_b values) (i) 9.30 (ii) 9.38 (iii) 4.75 (iv) 3.27

Choose the correct answer from the options given below:

A

(a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)

B

(a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)

C

(a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)

D

(a)-(i), (b)-(iv), (c)-(iii), (d)-(ii)

Step-by-Step Solution

The basic strength of an amine is inversely proportional to its pKbpK_b value. A lower pKbpK_b value indicates a stronger base.

  1. N-Methylmethanamine (dimethylamine) is a secondary aliphatic amine. It is the strongest base among the given choices due to the electron-donating inductive effect (+I effect) of two methyl groups and favourable solvation effects. Therefore, it has the lowest pKbpK_b of 3.27. [(a) \rightarrow (iv)]
  2. Ammonia (NH3NH_3) lacks alkyl groups but also lacks an electron-withdrawing aryl group. It is less basic than aliphatic amines but more basic than aromatic amines, having a pKbpK_b of 4.75. [(b) \rightarrow (iii)]
  3. Benzenamine (aniline) is a primary aromatic amine. The lone pair of electrons on the nitrogen is delocalised over the benzene ring, making it a much weaker base. Its pKbpK_b is 9.38. [(d) \rightarrow (ii)]
  4. N-Methylaniline is a secondary aromatic amine. The presence of one methyl group (+I effect) increases the electron density on nitrogen slightly compared to aniline, making it slightly more basic. Hence, its pKbpK_b is lower than aniline at 9.30. [(c) \rightarrow (i)]

Therefore, the correct matching is (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii).

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