Back to Directory
NEET CHEMISTRYMedium

Considering the following reaction, 3MnO42+2H2O2MnO4+MnO2+4OH3 MnO_4^{2-} + 2 H_2O \rightleftharpoons 2 MnO_4^{-} + MnO_2 + 4 OH^{-} The reagent that facilitates the removal of OHOH^{-} ions to ensure the completion of the conversion of K2MnO4K_2MnO_4 to KMnO4KMnO_4 is:

A

KOH

B

CO₂

C

SO₂

D

HCl

Step-by-Step Solution

The conversion of manganate ion (MnO42MnO_4^{2-}) to permanganate ion (MnO4MnO_4^-) is a disproportionation reaction that takes place in a neutral or acidic solution . The given reaction represents an equilibrium where hydroxide ions (OHOH^-) are produced.

  1. Le Chatelier's Principle: To drive the reaction to the right (completion), the concentration of the product OHOH^- must be reduced. This requires an acidic reagent to neutralize the base.
  2. Evaluating Reagents:
  • KOH: Being a strong base, it increases [OH][OH^-], shifting the equilibrium to the left (reactants), thus preventing the conversion.
  • HCl: While acidic, HClHCl acts as a reducing agent. Permanganate oxidises HClHCl to chlorine (Cl2Cl_2), consuming the desired product .
  • SO₂: Sulphur dioxide is a strong reducing agent that would reduce the permanganate formed (MnO4MnO_4^-) to Manganese(II) (Mn2+Mn^{2+}), destroying the product .
  • CO₂: Carbon dioxide is a weakly acidic oxide. It reacts with OHOH^- to form carbonate/bicarbonate, effectively removing OHOH^- from the equilibrium and driving the reaction forward without acting as a reducing agent towards the permanganate.
Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started