Solved: CHEMISTRY Question for NEET

NEET CHEMISTRYMedium

In the neutral or faintly alkaline medium, $KMnO_4$ oxidises iodide into iodate. The change in oxidation state of manganese in this reaction is from:

+6 to +5

+7 to +4

+6 to +4

+7 to +3

Step-by-Step Solution

In a neutral or faintly alkaline medium, permanganate ( $MnO_4^-$ ) oxidises iodide ( $I^-$ ) to iodate ( $IO_3^-$ ). The reaction is given as: $2MnO_4^- + H_2O + I^- \rightarrow 2MnO_2 + 2OH^- + IO_3^-$ In this reaction, manganese is reduced from the +7 oxidation state in $MnO_4^-$ to the +4 oxidation state in $MnO_2$ .

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