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A few reactions are given below: (i) CH3CH2CH2Br+KOHCH3CH=CH2+KBr+H2O\text{CH}_3\text{CH}_2\text{CH}_2\text{Br} + \text{KOH} \rightarrow \text{CH}_3\text{CH=CH}_2 + \text{KBr} + \text{H}_2\text{O} (ii) [Missing] (iii) [Missing] Select the reaction type for the above reactions:

A

Elimination, Substitution, Addition

B

Elimination, Substitution, Substitution

C

Substitution, Addition, Addition

D

Elimination, Elimination, Addition

Step-by-Step Solution

Reaction (i) is a dehydrohalogenation reaction, which is a type of elimination reaction (specifically, β\beta-elimination). In this reaction, a molecule of hydrogen bromide (HBr\text{HBr}) is removed from 1-bromopropane in the presence of alcoholic KOH to form an alkene (propene). Since the complete chemical equations for reactions (ii) and (iii) are missing from the provided input data, the remaining sequence of reaction types cannot be independently evaluated. Therefore, the exact correct option cannot be definitively verified from the given text.

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