What is the change in oxidation number of carbon in the following reaction? CH4(g)+4Cl2(g)→CCl4(l)+4HCl(g)\text{CH}_4(g) + 4\text{Cl}_2(g) \rightarrow \text{CCl}_4(l) + 4\text{HCl}(g)CH4(g)+4Cl2(g)→CCl4(l)+4HCl(g)
0 to + 4
0 to - 4
In CH4\text{CH}_4CH4, x+4×1=0⇒x=−4\text{x} + 4 \times 1 = 0 \Rightarrow \text{x} = -4x+4×1=0⇒x=−4. In CCl4\text{CCl}_4CCl4, x+4×(−1)=0⇒x=+4\text{x} + 4 \times (-1) = 0 \Rightarrow \text{x} = +4x+4×(−1)=0⇒x=+4. Change is from -4 to +4.
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