Back to Directory
NEET CHEMISTRYMedium

A and B in the following reactions are: (i) RC(O)Cl+H2Pd/BaSO4AR-C(O)Cl + H_2 \xrightarrow{Pd/BaSO_4} A (ii) RCN+SnCl2+HClH3O+BR-C \equiv N + SnCl_2 + HCl \xrightarrow{H_3O^+} B

A

A = RCOOH, B = RCHO

B

A = RCHO, B = RCOOH

C

A = RCH_2OH, B = RCHO

D

A = RCHO, B = RCHO

Step-by-Step Solution

  1. Reaction (i): Rosenmund Reduction Acyl chlorides (RCOClRCOCl) are hydrogenated over a catalyst, palladium on barium sulphate (Pd/BaSO4Pd/BaSO_4). This reaction is used exclusively for the preparation of aldehydes (RCHORCHO). The catalyst is poisoned with sulphur or quinoline to prevent further reduction to primary alcohols. RCOCl+H2Pd/BaSO4RCHO+HClRCOCl + H_2 \xrightarrow{Pd/BaSO_4} RCHO + HCl

  2. Reaction (ii): Stephen Reaction Nitriles (RCNRCN) are reduced to imines with stannous chloride in the presence of hydrochloric acid (SnCl2+HClSnCl_2 + HCl), which on hydrolysis give the corresponding aldehyde (RCHORCHO). RCN+SnCl2+HClRCH=NHH3O+RCHORCN + SnCl_2 + HCl \rightarrow RCH=NH \xrightarrow{H_3O^+} RCHO

Thus, both products A and B are aldehydes (RCHORCHO).

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started
Solved: CHEMISTRY Question for NEET | Sushrut