Back to Directory
NEET CHEMISTRYEasy

The correct option for the rate law that corresponds to an overall first-order reaction is:

A

Rate=k[A]0[B]2\text{Rate} = k[A]^0[B]^2

B

Rate=k[A][B]\text{Rate} = k[A][B]

C

Rate=k[A]1/2[B]2\text{Rate} = k[A]^{1/2}[B]^2

D

Rate=k[A]−1/2[B]3/2\text{Rate} = k[A]^{-1/2}[B]^{3/2}

Step-by-Step Solution

The overall order of a reaction is the sum of the exponents of the concentration terms in the rate law expression. For a general rate law, Rate=k[A]x[B]y\text{Rate} = k[A]^x[B]^y, the overall order is n=x+yn = x + y. Checking the given options:

  1. Rate=k[A]0[B]2\text{Rate} = k[A]^0[B]^2: Order =0+2=2= 0 + 2 = 2
  2. Rate=k[A]1[B]1\text{Rate} = k[A]^1[B]^1: Order =1+1=2= 1 + 1 = 2
  3. Rate=k[A]1/2[B]2\text{Rate} = k[A]^{1/2}[B]^2: Order =12+2=2.5= \frac{1}{2} + 2 = 2.5
  4. Rate=k[A]−1/2[B]3/2\text{Rate} = k[A]^{-1/2}[B]^{3/2}: Order =−12+32=22=1= -\frac{1}{2} + \frac{3}{2} = \frac{2}{2} = 1 Therefore, the rate law Rate=k[A]−1/2[B]3/2\text{Rate} = k[A]^{-1/2}[B]^{3/2} corresponds to an overall first-order reaction.
Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started
Solved: CHEMISTRY Question for NEET | Sushrut