The crystal field stabilisation energy (CFSE) and the 'spin only' magnetic moment of [FeF6]3− ion respectively, are:
A
0Δo and 5.9 BM
B
0Δo and 1.73 BM
C
2.0Δo and 5.9 BM
D
2.0Δo and 1.73 BM
Step-by-Step Solution
In the complex [FeF6]3−, the central metal ion is Iron (Fe) in the +3 oxidation state. The electronic configuration of Fe3+ is 3d5.
Since the fluoride ion (F−) is a weak field ligand, the crystal field splitting energy (Δo) is less than the pairing energy (P). Therefore, the pairing of electrons does not occur, and it forms a high-spin complex.
The distribution of 5 electrons in the d-orbitals will be t2g3eg2.
Calculation of CFSE:CFSE=(−0.4×nt2g+0.6×neg)ΔoCFSE=(−0.4×3+0.6×2)Δo=(−1.2+1.2)Δo=0Δo.
Calculation of Magnetic Moment:
The number of unpaired electrons (n) in t2g3eg2 is 5.
The spin-only magnetic moment (μ) is given by μ=n(n+2) BM.
μ=5(5+2)=35≈5.92 BM.
Therefore, the CFSE is 0Δo and the spin-only magnetic moment is 5.9 BM.
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