Back to Directory
NEET CHEMISTRYMedium

The compound that gives a pair of enantiomorphs is: (en = NH₂CH₂CH₂NH₂)

A

[Co(NH₃)₄Cl₂]NO₂

B

[Cr(NH₃)₆][Co(CN)₆]

C

[Co(en)₂Cl₂]Cl

D

[Pt(NH₃)₄][PtCl₆]

Step-by-Step Solution

Enantiomorphs (or enantiomers) are mirror images that are non-superimposable, a property known as chirality or optical activity. This typically occurs in octahedral complexes involving didentate ligands.

  1. Analysis of [Co(en)₂Cl₂]Cl: The complex ion is [Co(en)2Cl2]+[Co(en)_2Cl_2]^+. This is an octahedral complex of the type [M(AA)2a2][M(AA)_2a_2], where 'AA' is the bidentate ligand ethylenediamine (enen) and 'a' is the monodentate ligand chloride (ClCl^-).
  • It exhibits Geometrical Isomerism (cis and trans).
  • The Trans-isomer has a plane of symmetry and is optically inactive (achiral).
  • The Cis-isomer lacks a plane of symmetry and is chiral. Therefore, the cis-isomer exists as a pair of enantiomorphs (dextro and laevo forms) .
  1. Other Options: [Co(NH3)4Cl2]NO2[Co(NH_3)_4Cl_2]NO_2: Type [Ma4b2][Ma_4b_2]. The cis-isomer is usually considered achiral in this context relative to the chelated complex, and the trans-isomer is definitely achiral. [Cr(NH3)6][Co(CN)6][Cr(NH_3)_6][Co(CN)_6]: Both ions are highly symmetrical octahedral species and do not show optical isomerism.
  • [Pt(NH3)4][PtCl6][Pt(NH_3)_4][PtCl_6]: Contains a square planar cation and octahedral anion, neither of which supports enantiomerism in this form.

Therefore, [Co(en)2Cl2]Cl[Co(en)_2Cl_2]Cl is the compound that gives a pair of enantiomorphs.

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started
Solved: CHEMISTRY Question for NEET | Sushrut