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NEET CHEMISTRYEasy

Which of the following contains 0.5 moles of a solute in one molal solution?

A

1000 g of solvent

B

500 mL of solvent

C

500 g of solvent

D

100 mL of solvent

Step-by-Step Solution

Molality (mm) is defined as the number of moles of solute dissolved per kilogram (1000 g) of the solvent . Molality (m)=Moles of soluteMass of solvent in kg\text{Molality (m)} = \frac{\text{Moles of solute}}{\text{Mass of solvent in kg}} Given: Molality (mm) = 1 m=1 mol kg11 \text{ m} = 1 \text{ mol kg}^{-1} Moles of solute (nn) = 0.5 mol0.5 \text{ mol} Substituting the values: 1=0.5Mass of solvent in kg1 = \frac{0.5}{\text{Mass of solvent in kg}} Mass of solvent in kg=0.5 kg\text{Mass of solvent in kg} = 0.5 \text{ kg} Since 1 kg=1000 g1 \text{ kg} = 1000 \text{ g}, the mass of the solvent is 0.5×1000 g=500 g0.5 \times 1000 \text{ g} = 500 \text{ g}.

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