Back to Directory
NEET CHEMISTRYEasy

Which pair of ions among the following list do not constitute an iso-electronic pair?

A

Mn2+,Fe3+Mn^{2+}, Fe^{3+}

B

Fe2+,Mn2+Fe^{2+}, Mn^{2+}

C

O2,FO^{2–}, F^{–}

D

Na+,Mg2+Na^+, Mg^{2+}

Step-by-Step Solution

According to the sources, isoelectronic species are atoms and ions that contain the same number of electrons . To determine if a pair is isoelectronic, we calculate the electron count for each ion based on its atomic number (ZZ) and its charge:

  1. Mn2+Mn^{2+} and Fe3+Fe^{3+}: Manganese (Z=25Z=25) loses two electrons to have 23, and Iron (Z=26Z=26) loses three electrons to have 23. They are isoelectronic .
  2. Fe2+Fe^{2+} and Mn2+Mn^{2+}: Fe2+Fe^{2+} has 262=2426 - 2 = 24 electrons, while Mn2+Mn^{2+} has 252=2325 - 2 = 23 electrons. Because their electron counts differ, they are not isoelectronic .
  3. O2O^{2–} and FF^{–}: Oxygen (Z=8Z=8) gains two and Fluorine (Z=9Z=9) gains one; both result in 10 electrons .
  4. Na+Na^+ and Mg2+Mg^{2+}: Sodium (Z=11Z=11) loses one and Magnesium (Z=12Z=12) loses two; both result in 10 electrons .

Therefore, the pair Fe2+,Mn2+Fe^{2+}, Mn^{2+} does not constitute an isoelectronic pair.

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started
Solved: CHEMISTRY Question for NEET | Sushrut