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NEET CHEMISTRYMedium

The molar conductance of NaCl\text{NaCl}, HCl\text{HCl} and CH3COONa\text{CH}_3\text{COONa} at infinite dilution are 126.45126.45, 426.16426.16 and 91.0 S cm2 mol−191.0 \text{ S cm}^2 \text{ mol}^{-1} respectively. The molar conductance of CH3COOH\text{CH}_3\text{COOH} at infinite dilution is. Choose the right option for your answer.

1

201.28 S cm2 mol−1201.28 \text{ S cm}^2 \text{ mol}^{-1}

2

390.71 S cm2 mol−1390.71 \text{ S cm}^2 \text{ mol}^{-1}

3

698.28 S cm2 mol−1698.28 \text{ S cm}^2 \text{ mol}^{-1}

4

540.48 S cm2 mol−1540.48 \text{ S cm}^2 \text{ mol}^{-1}

Step-by-Step Solution

According to Kohlrausch law of independent migration of ions. Λmo(CH3COOH)=Λmo(CH3COONa)+Λmo(HCl)−Λmo(NaCl)=91.0+426.16−126.45=390.71 S cm2 mol−1\Lambda_m^o(\text{CH}_3\text{COOH}) = \Lambda_m^o(\text{CH}_3\text{COONa}) + \Lambda_m^o(\text{HCl}) - \Lambda_m^o(\text{NaCl}) = 91.0 + 426.16 - 126.45 = 390.71 \text{ S cm}^2 \text{ mol}^{-1}

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