The reaction of an aromatic compound with halogens like $\text{Br}_2$ in the presence of a Lewis acid (such as anhydrous $\text{FeBr}_3$ or $\text{AlCl}_3$) is an electrophilic aromatic substitution reaction . The Lewis acid helps generate the active electrophile ($\text{Br}^+$), which attacks the electron-rich benzene ring . The exact position of the newly attached bromine atom(s)—whether ortho, meta, or para—depends entirely on the directive influence of the functional groups already present on the parent aromatic compound . Because the structure of the starting compound is missing from the input data, the specific product cannot be deduced.

Note: Option 4 is marked correct based solely on the provided probable answer.