Back to Directory
NEET CHEMISTRYMedium

In the reaction, CH3CN+2HHClSnCl2XboilingH2OYCH_3CN + 2H \xrightarrow[HCl]{SnCl_2} X \xrightarrow{boiling H_2O} Y the term Y is:

A

Acetone

B

Ethanamine

C

Acetaldehyde

D

Dimethyl amine

Step-by-Step Solution

The reaction sequence shown is the Stephen reaction, used for the preparation of aldehydes from nitriles (cyanides).

  1. Reduction: Methyl cyanide (CH3CNCH_3CN) is partially reduced by stannous chloride (SnCl2SnCl_2) in the presence of hydrochloric acid (HClHCl) to form an imine hydrochloride intermediate (X). CH3CN+2[H]+HClSnCl2CH3CH=NHHCl (Acetaldimine hydrochloride)CH_3CN + 2[H] + HCl \xrightarrow{SnCl_2} CH_3CH=NH \cdot HCl \text{ (Acetaldimine hydrochloride)}
  2. Hydrolysis: The imine intermediate (X) undergoes hydrolysis with boiling water to yield acetaldehyde (Y). CH3CH=NHHCl+H2OΔCH3CHO+NH4ClCH_3CH=NH \cdot HCl + H_2O \xrightarrow{\Delta} CH_3CHO + NH_4Cl Thus, Y is Acetaldehyde (CH3CHOCH_3CHO).
Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started
Solved: CHEMISTRY Question for NEET | Sushrut