NaOH is a strong base and dissociates completely in water. Concentration of hydroxyl ions, $[\text{OH}^-] = 0.01\text{ M} = 10^{-2}\text{ M}$ We know that $\text{pOH} = -\log[\text{OH}^-]$ $\text{pOH} = -\log(10^{-2}) = 2$ At $298\text{ K}$, the relationship between pH and pOH is given by: $\text{pH} + \text{pOH} = 14$ $\text{pH} = 14 - 2 = 12$ Therefore, the pH of the solution is $12$.