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NEET CHEMISTRYEasy

The correct relation between dissociation constants of a di-basic acid is:

A

Ka1=Ka2K_{a1} = K_{a2}

B

Ka1>Ka2K_{a1} > K_{a2}

C

Ka1<Ka2K_{a1} < K_{a2}

D

Ka1=1/Ka2K_{a1} = 1/K_{a2}

Step-by-Step Solution

For a di-basic (or diprotic) acid, the dissociation occurs in two successive steps. For example, considering a general di-basic acid H2XH_2X: Step 1: H2XH++HXH_2X \rightleftharpoons H^+ + HX^- (First dissociation constant, Ka1K_{a1}) Step 2: HXH++X2HX^- \rightleftharpoons H^+ + X^{2-} (Second dissociation constant, Ka2K_{a2})

It is more difficult to remove a positively charged proton (H+H^+) from a negatively charged ion (HXHX^-) due to electrostatic forces of attraction compared to removing it from a neutral molecule (H2XH_2X). Therefore, the first dissociation constant (Ka1K_{a1}) is always greater than the second dissociation constant (Ka2K_{a2}). Thus, Ka1>Ka2K_{a1} > K_{a2} .

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