Solved: CHEMISTRY Question for NEET

NEET CHEMISTRYEasy

If an atom has electronic configuration $1s^2 2s^2 2p^6 3s^2 3p^6 3d^3 4s^2$ , we will place it in group number:

Fifth

Fifteenth

Second

Third

Identify the Block: The electronic configuration ends with electrons filling the $3d$ orbital ( $3d^3$ ) after the $4s$ orbital ( $4s^2$ ). This indicates the element belongs to the d-block (Transition Elements).
Determine the Group Number: For d-block elements, the group number is calculated as the sum of electrons in the $(n-1)d$ subshell and the $ns$ subshell. Group Number = (Number of electrons in $3d$ ) + (Number of electrons in $4s$ ) Group Number = $3 + 2 = 5$
Identify the Element (Optional): The total number of electrons is $2+2+6+2+6+3+2 = 23$ . The element with atomic number 23 is Vanadium (V), which lies in Group 5.

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