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NEET CHEMISTRYEasy

If the half-life of a substance is 77 days77 \text{ days} then its decay constant (days1\text{days}^{-1}) will be:

A

0.9

B

0.09

C

0.009

D

0.013

Step-by-Step Solution

Radioactive decay follows first-order kinetics. The decay constant (kk or λ\lambda) is related to the half-life (t1/2t_{1/2}) by the relation:

k=0.693t1/2k = \frac{0.693}{t_{1/2}}

Given: Half-life, t1/2=77 dayst_{1/2} = 77 \text{ days}

Substituting the given value: k=0.69377 days=0.009 days1k = \frac{0.693}{77 \text{ days}} = 0.009 \text{ days}^{-1}.

Therefore, the decay constant is 0.009 days10.009 \text{ days}^{-1}.

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