Back to Directory
NEET CHEMISTRYMedium

Propanoic acid with Br2/PBr_2/P yields a dibromo product. Its structure would be:

A

CH₂Br−CHBr−COOH

B

Option 2 (Image Missing)

C

CH₂Br−CH₂−COBr

D

CH₃−CBr₂−COOH

Step-by-Step Solution

The reaction of carboxylic acids having α\alpha-hydrogens with chlorine or bromine in the presence of small amount of red phosphorus is known as the Hell-Volhard-Zelinsky (HVZ) reaction.

  1. Specificity: This reaction results in the substitution of α\alpha-hydrogens (hydrogens attached to the carbon adjacent to the COOH-COOH group) by halogen atoms.
  2. Reactant: Propanoic acid is CH3CH2COOHCH_3-CH_2-COOH. The α\alpha-carbon is the CH2-CH_2- group, which contains two α\alpha-hydrogens.
  3. Product: If the reaction yields a 'dibromo' product, both α\alpha-hydrogens are replaced by bromine atoms.

CH3CH2COOHBr2/PCH3C(Br)2COOHCH_3-CH_2-COOH \xrightarrow{Br_2/P} CH_3-C(Br)_2-COOH

The product is 2,2-Dibromopropanoic acid (CH3CBr2COOHCH_3-CBr_2-COOH). Option 1 represents α,β\alpha,\beta-substitution which is incorrect for HVZ.

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started
Solved: CHEMISTRY Question for NEET | Sushrut