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NEET CHEMISTRYMedium

What is the correct family and electronic configuration for element Z = 114?

A

Halogen family, [Rn]5f^{14}6d^{10}7s^27p^5

B

Carbon family, [Rn]5f^{14}6d^{10}7s^27p^2

C

Oxygen family, [Rn]5f^{14}6d^{10}7s^27p^4

D

Nitrogen family, [Rn]5f^{14}6d^{10}7s^27p^6

Step-by-Step Solution

To determine the position and configuration of the element with atomic number Z=114Z = 114:

  1. Identify the preceding Noble Gas: Radon (86Rn^{86}\text{Rn}) is the noble gas ending the 6th period.
  2. Fill orbitals for the 7th period: According to the Aufbau principle, electrons fill the 7s7s, 5f5f, 6d6d, and 7p7p orbitals in that order. Z=86Z = 86 (Rn) Add 2 electrons to 7s7s: 86+2=8886 + 2 = 88 Add 14 electrons to 5f5f: 88+14=10288 + 14 = 102 Add 10 electrons to 6d6d: 102+10=112102 + 10 = 112
  3. Determine valence electrons: We have 114112=2114 - 112 = 2 electrons remaining. These go into the 7p7p orbital.
  • Configuration: [Rn]5f146d107s27p2[\text{Rn}] 5f^{14} 6d^{10} 7s^2 7p^2.
  1. Identify the Family: The general valence shell configuration ns2np2ns^2 np^2 corresponds to Group 14, which is the Carbon family.
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