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NEET CHEMISTRYEasy

For a reaction 3A→2B3A \rightarrow 2B, the average rate of appearance of B is given by Δ[B]Δt\frac{\Delta [B]}{\Delta t}. The correct relation between the average rate of appearance of B with the average rate of disappearance of A is:

A

−Δ[A]Δt-\frac{\Delta [A]}{\Delta t}

B

−3Δ[A]2Δt-\frac{3\Delta [A]}{2\Delta t}

C

−2Δ[A]3Δt-\frac{2\Delta [A]}{3\Delta t}

D

Δ[A]Δt\frac{\Delta [A]}{\Delta t}

Step-by-Step Solution

For the given reaction 3A→2B3A \rightarrow 2B, the rate of the reaction can be expressed in terms of the disappearance of reactant A and the appearance of product B as follows: Rate of reaction=−13Δ[A]Δt=+12Δ[B]Δt\text{Rate of reaction} = -\frac{1}{3}\frac{\Delta [A]}{\Delta t} = +\frac{1}{2}\frac{\Delta [B]}{\Delta t} To find the relation for the average rate of appearance of B, we rearrange the equation: Δ[B]Δt=−23Δ[A]Δt\frac{\Delta [B]}{\Delta t} = -\frac{2}{3}\frac{\Delta [A]}{\Delta t}

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