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NEET CHEMISTRYEasy

Determine ΔU\Delta U for the process where, one mole of an ideal gas at 300 K300 \text{ K} is expanded isothermally from 1 L1 \text{ L} to 10 L10 \text{ L} volume: (Use R=8.314 J K−1 mol−1R = 8.314 \text{ J K}^{-1} \text{ mol}^{-1})

A

1260 J

B

2520 J

C

5040 J

D

0 J

Step-by-Step Solution

For an ideal gas, the internal energy is a function of absolute temperature only. In an isothermal process, the temperature remains constant (ΔT=0\Delta T = 0). Therefore, the change in internal energy (ΔU\Delta U) is also zero .

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