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NEET CHEMISTRYEasy

Which one is not equal to zero for an ideal solution?

A

ΔHmix\Delta H_{\text{mix}}

B

ΔSmix\Delta S_{\text{mix}}

C

ΔVmix\Delta V_{\text{mix}}

D

ΔP=PObservedPRaoult\Delta P = P_{\text{Observed}} - P_{\text{Raoult}}

Step-by-Step Solution

For an ideal solution, it perfectly obeys Raoult's law over the entire range of concentrations, meaning the observed vapour pressure matches the pressure calculated by Raoult's law (ΔP=0\Delta P = 0). Furthermore, the intermolecular attractive forces between the components (A-B) are nearly equal to those in the pure components (A-A and B-B). This results in zero enthalpy of mixing (ΔHmix=0\Delta H_{\text{mix}} = 0) and zero volume of mixing (ΔVmix=0\Delta V_{\text{mix}} = 0). However, the mixing of two miscible liquids is a spontaneous process that leads to an increase in the randomness or disorder of the system. Therefore, the entropy of mixing is always positive (ΔSmix>0\Delta S_{\text{mix}} > 0) and is never equal to zero.

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