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NEET CHEMISTRYMedium

For the chemical reaction N2(g)+3H2(g)⇌2NH3(g)N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g), the correct option is:

1

−13d[H2]dt=12d[NH3]dt-\frac{1}{3} \frac{d[H_2]}{dt} = \frac{1}{2} \frac{d[NH_3]}{dt}

2

−d[N2]dt=2d[NH3]dt-\frac{d[N_2]}{dt} = 2 \frac{d[NH_3]}{dt}

3

−d[N2]dt=12d[NH3]dt-\frac{d[N_2]}{dt} = \frac{1}{2} \frac{d[NH_3]}{dt}

4

3d[H2]dt=2d[NH3]dt3 \frac{d[H_2]}{dt} = 2 \frac{d[NH_3]}{dt}

Step-by-Step Solution

For the reaction N2+3H2⇌2NH3N_2 + 3H_2 \rightleftharpoons 2NH_3, the rate of reaction is given by: −d[N2]dt=−13d[H2]dt=+12d[NH3]dt-\frac{d[N_2]}{dt} = -\frac{1}{3} \frac{d[H_2]}{dt} = +\frac{1}{2} \frac{d[NH_3]}{dt}. Thus, −d[N2]dt=12d[NH3]dt-\frac{d[N_2]}{dt} = \frac{1}{2} \frac{d[NH_3]}{dt}.

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