Solved: CHEMISTRY Question for NEET

NEET CHEMISTRYMedium

The common oxidation state shown by actinoids is +3 with the other oxidation states being +4, +5, +6, and +7. Rank the following elements in decreasing order of the number of oxidation states they display: A. Np ( $Z=93$ ) B. Am ( $Z=95$ ) C. Ac ( $Z=89$ ) D. Pa ( $Z=91$ )

Choose the correct answer from the options given below:

A > B > D > C

A > B > C > D

B > A > D > C

D > B > A > C

Step-by-Step Solution

According to the known oxidation states of actinoids :

Np (Neptunium, $Z=93$ ) exhibits 5 oxidation states: +3, +4, +5, +6, and +7.
Am (Americium, $Z=95$ ) exhibits 4 oxidation states: +3, +4, +5, and +6.
Pa (Protactinium, $Z=91$ ) exhibits 3 oxidation states: +3, +4, and +5.
Ac (Actinium, $Z=89$ ) exhibits only 1 oxidation state: +3. Therefore, the decreasing order of the number of oxidation states displayed is Np > Am > Pa > Ac, which corresponds to the sequence A > B > D > C.

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