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NEET CHEMISTRYMedium

A gas at 350 K350\text{ K} and 15 bar15\text{ bar} has molar volume 2020 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z)(Z) is :

1

Z>1Z > 1 and attractive forces are dominant

2

Z>1Z > 1 and repulsive forces are dominant

3

Z<1Z < 1 and attractive forces are dominant

4

Z<1Z < 1 and repulsive forces are dominant

Step-by-Step Solution

Compressibility factor (Z)=VrealVideal(Z) = \frac{V_{real}}{V_{ideal}}. ∵Vreal<Videal\because V_{real} < V_{ideal}; Hence Z<1Z < 1. If Z<1Z < 1, attractive forces are dominant among gaseous molecules and liquefaction of gas will be easy.

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