The conversion of propene ($\text{CH}_3\text{-CH}=\text{CH}_2$) to 1-propanol ($\text{CH}_3\text{-CH}_2\text{-CH}_2\text{OH}$) involves the overall addition of water across the double bond in an anti-Markovnikov fashion. This specific transformation is achieved through the hydroboration-oxidation reaction.

In the first step, propene reacts with diborane ($\text{B}_2\text{H}_6$) to undergo hydroboration, forming a trialkylborane intermediate. In the second step, the intermediate is oxidized using hydrogen peroxide ($\text{H}_2\text{O}_2$) in the presence of an aqueous base ($\text{OH}^-$) to yield the primary alcohol, 1-propanol.

• Option A ($\text{H}_2\text{O}, \text{H}_2\text{SO}_4$) and Option C ($\text{Hg(OAc)}_2, \text{NaBH}_4/\text{H}_2\text{O}$) lead to Markovnikov addition of water, which would yield 2-propanol .
• Option D (Aq. KOH) is a reagent typically used for nucleophilic substitution of alkyl halides to form alcohols, not for direct addition to alkenes.