According to the definition of electric current, the total charge ($Q$) passed is the product of current ($I$) and time ($t$). $Q = I \times t$ Given: $I = 1 \text{ A}$ $t = 60 \text{ s}$ $Q = 1 \text{ A} \times 60 \text{ s} = 60 \text{ C}$ The total charge is also equal to the number of electrons ($n$) multiplied by the charge of a single electron ($e$). $Q = n \times e$ $n = \frac{Q}{e} = \frac{60 \text{ C}}{1.60 \times 10^{-19} \text{ C}}$ $n = 37.5 \times 10^{19} = 3.75 \times 10^{20}$ Therefore, the number of electrons delivered at the cathode is $3.75 \times 10^{20}$.