Solved: CHEMISTRY Question for NEET | Sushrut

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NEET CHEMISTRYEasy

The percentages of C, H, and N in an organic compound are 40%, 13.3%, and 46.7% respectively. The empirical formula of the compound is:

A

C₃H₁₃N₃

B

CH₂N

C

CH₄N

D

CH₆N

Step-by-Step Solution

Determine the number of moles of each element: Assume a $100\text{ g}$ sample of the compound to directly convert percentages to mass.

Moles of Carbon (C): $\frac{40\text{ g}}{12\text{ g/mol}} = 3.33\text{ mol}$
Moles of Hydrogen (H): $\frac{13.3\text{ g}}{1\text{ g/mol}} = 13.3\text{ mol}$
Moles of Nitrogen (N): $\frac{46.7\text{ g}}{14\text{ g/mol}} \approx 3.335\text{ mol}$

Determine the simplest molar ratio: Divide the mole values by the smallest number of moles calculated ( $3.33\text{ mol}$ ).

Ratio for C: $\frac{3.33}{3.33} = 1$
Ratio for H: $\frac{13.3}{3.33} \approx 4$
Ratio for N: $\frac{3.335}{3.33} \approx 1$

Construct the Formula: The simplest whole number ratio of C:H:N is $1:4:1$ . Therefore, the empirical formula is $\text{CH}_4\text{N}$ .

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Solved: CHEMISTRY Question for NEET | Sushrut