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NEET CHEMISTRYMedium

Find the molarity of liquid HCl if the density of liquid HCl is 1.17 g/cc1.17\text{ g/cc}.

A

36.5

B

18.25

C

32.05

D

42.1

Step-by-Step Solution

  1. Identify the Definition: Molarity (MM) is defined as the number of moles of solute dissolved in one litre of solution .
  2. Assumption: Consider exactly 1 Litre1\text{ Litre} (1000 cc1000\text{ cc} or 1000 mL1000\text{ mL}) of the liquid HCl.
  3. Calculate Mass: Using the given density (d=1.17 g/ccd = 1.17\text{ g/cc}): Mass=Density×Volume=1.17 g/cc×1000 cc=1170 g\text{Mass} = \text{Density} \times \text{Volume} = 1.17\text{ g/cc} \times 1000\text{ cc} = 1170\text{ g}
  4. Calculate Moles: The molar mass of HCl (1+35.51 + 35.5) is 36.5 g/mol36.5\text{ g/mol}. Moles(n)=MassMolar Mass=117036.532.05 mol\text{Moles} (n) = \frac{\text{Mass}}{\text{Molar Mass}} = \frac{1170}{36.5} \approx 32.05\text{ mol}
  5. Calculate Molarity: M=nV(in L)=32.05 mol1 L=32.05 MM = \frac{n}{V(\text{in L})} = \frac{32.05\text{ mol}}{1\text{ L}} = 32.05\text{ M}
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