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NEET CHEMISTRYMedium

Which of the following is a coloured and paramagnetic compound?

A

CuF2\text{CuF}_2

B

K2Cr2O7\text{K}_2\text{Cr}_2\text{O}_7

C

KMnO4\text{KMnO}_4

D

K4[Fe(CN)6]\text{K}_4[\text{Fe(CN)}_6]

Step-by-Step Solution

Colour and paramagnetism in transition metal compounds generally arise due to the presence of unpaired d-electrons.

  • In CuF2\text{CuF}_2, the oxidation state of Cu is +2+2. Its electronic configuration is [Ar]3d9[\text{Ar}] 3d^9, which has one unpaired electron. Thus, it is paramagnetic and coloured due to d-d transitions.
  • In K2Cr2O7\text{K}_2\text{Cr}_2\text{O}_7, the oxidation state of Cr is +6+6. Its electronic configuration is [Ar]3d0[\text{Ar}] 3d^0, which has zero unpaired electrons. Thus, it is diamagnetic (though it is coloured due to ligand-to-metal charge transfer).
  • In KMnO4\text{KMnO}_4, the oxidation state of Mn is +7+7. Its electronic configuration is [Ar]3d0[\text{Ar}] 3d^0, which has zero unpaired electrons. Thus, it is diamagnetic (also coloured due to charge transfer).
  • In K4[Fe(CN)6]\text{K}_4[\text{Fe(CN)}_6], the oxidation state of Fe is +2+2 (3d63d^6). Since CN\text{CN}^- is a strong field ligand, all six d-electrons pair up in the lower energy t2gt_{2g} level, leaving zero unpaired electrons. Thus, it is diamagnetic.
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