According to Kohlrausch's law of independent migration of ions, the equivalent conductance of an electrolyte at infinite dilution is equal to the sum of the equivalent conductances of its constituent ions at infinite dilution.

$\Lambda^{\circ}_{eq}(BaCl_2) = \lambda^{\circ}_{eq}(Ba^{2+}) + \lambda^{\circ}_{eq}(Cl^-)$

Given: $\lambda^{\circ}_{eq}(Ba^{2+}) = 127 \text{ ohm}^{-1}\text{cm}^{-1}\text{ eq}^{-1}$ $\lambda^{\circ}_{eq}(Cl^-) = 76 \text{ ohm}^{-1}\text{cm}^{-1}\text{ eq}^{-1}$

$\Lambda^{\circ}_{eq}(BaCl_2) = 127 + 76 = 203 \text{ ohm}^{-1}\text{cm}^{-1}\text{ eq}^{-1}$

Note: For equivalent conductance, we simply add the equivalent conductances of the ions. The stoichiometric coefficients are not multiplied as they are in the case of molar conductance.