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NEET CHEMISTRYEasy

Among the options given below, identify the isoelectronic species:

A

CO,CN,NO+,C22CO, CN^{-}, NO^{+}, C_{2}^{2-}

B

CO,CN,NO,C2CO^{-}, CN, NO, C_{2}^{-}

C

CO+,CN+,NO,C2CO^{+}, CN^{+}, NO^{-}, C_{2}

D

CO,CN,NO,C2CO, CN, NO, C_{2}

Step-by-Step Solution

Isoelectronic species are defined as atoms, ions, or molecules that possess the same total number of electrons . To identify the correct set, the total electron count for each species in Option A is calculated using their atomic numbers (ZZ) and ionic charges :

  1. COCO: Carbon (Z=6Z=6) + Oxygen (Z=8Z=8) = 1414 electrons .
  2. CNCN^{-}: Carbon (66) + Nitrogen (77) + 11 (for the negative charge) = 1414 electrons .
  3. NO+NO^{+}: Nitrogen (77) + Oxygen (88) - 11 (for the positive charge) = 1414 electrons .
  4. C22C_{2}^{2-}: Two Carbon atoms (2×62 \times 6) + 22 (for the 22- charge) = 1414 electrons.

Since every species in this group has exactly 1414 electrons, they are isoelectronic . Other options are incorrect because they include species with different electron counts, such as NONO (15 electrons) or CNCN (13 electrons) .

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