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NEET CHEMISTRYEasy

In a regular octahedral molecule, MX6MX_{6}, the number of XMXX–M–X bonds at 180º is:

A

Two

B

Six

C

Four

D

Three

Step-by-Step Solution

In a regular octahedral geometry, such as that found in SF6SF_{6}, the central metal atom is surrounded by six ligands . This arrangement consists of four ligands situated at the corners of a square plane with the central atom at its center, and two additional ligands positioned axially—one directly above and one directly below the plane . The XMXX–M–X bonds at 180º occur between pairs of ligands that are positioned diametrically opposite each other through the central atom. In this structure, there are exactly three such pairs: one axial pair (top to bottom) and two equatorial pairs (diagonally opposite corners of the square plane) .

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