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NEET CHEMISTRYMedium

For irreversible expansion of an ideal gas under isothermal conditions, the correct option is:

A

ΔU=0,ΔStotal0\Delta U = 0, \Delta S_{total} \neq 0

B

ΔU0,ΔStotal=0\Delta U \neq 0, \Delta S_{total} = 0

C

ΔU=0,ΔStotal=0\Delta U = 0, \Delta S_{total} = 0

D

ΔU0,ΔStotal0\Delta U \neq 0, \Delta S_{total} \neq 0

Step-by-Step Solution

For an ideal gas, internal energy is a function of temperature only. Since the process is isothermal, the change in temperature is zero (ΔT=0\Delta T = 0), which implies the change in internal energy is also zero (ΔU=0\Delta U = 0) . For any irreversible process, the total entropy change of the universe (system + surroundings) must be strictly positive (ΔStotal>0\Delta S_{total} > 0), meaning ΔStotal0\Delta S_{total} \neq 0 .

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