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KcK_c and KpK_p are not equal for a reaction given below:

A

2NO(g)N2(g)+O2(g)2NO(g) \rightleftharpoons N_2(g) + O_2(g)

B

SO2(g)+NO2(g)SO3(g)+NO(g)SO_2(g) + NO_2(g) \rightleftharpoons SO_3(g) + NO(g)

C

H2(g)+I2(g)2HI(g)H_2(g) + I_2(g) \rightleftharpoons 2HI(g)

D

2C(s)+O2(g)2CO2(g)2C(s) + O_2(g) \rightleftharpoons 2CO_2(g)

Step-by-Step Solution

The relationship between KpK_p and KcK_c is given by the equation: Kp=Kc(RT)ΔngK_p = K_c(RT)^{\Delta n_g}, where Δng\Delta n_g is the difference between the sum of the number of moles of gaseous products and the sum of the number of moles of gaseous reactants. For KpK_p to not be equal to KcK_c, Δng\Delta n_g must not be equal to zero. Let us calculate Δng\Delta n_g for each option:

  1. 2NO(g)N2(g)+O2(g)2NO(g) \rightleftharpoons N_2(g) + O_2(g); Δng=(1+1)2=0\Delta n_g = (1 + 1) - 2 = 0. Hence, Kp=KcK_p = K_c.
  2. SO2(g)+NO2(g)SO3(g)+NO(g)SO_2(g) + NO_2(g) \rightleftharpoons SO_3(g) + NO(g); Δng=(1+1)(1+1)=0\Delta n_g = (1 + 1) - (1 + 1) = 0. Hence, Kp=KcK_p = K_c.
  3. H2(g)+I2(g)2HI(g)H_2(g) + I_2(g) \rightleftharpoons 2HI(g); Δng=2(1+1)=0\Delta n_g = 2 - (1 + 1) = 0. Hence, Kp=KcK_p = K_c.
  4. 2C(s)+O2(g)2CO2(g)2C(s) + O_2(g) \rightleftharpoons 2CO_2(g); Δng=21=1\Delta n_g = 2 - 1 = 1. Since Δng0\Delta n_g \neq 0, KpKcK_p \neq K_c. Therefore, the correct option is the reaction 2C(s)+O2(g)2CO2(g)2C(s) + O_2(g) \rightleftharpoons 2CO_2(g).
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