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NEET CHEMISTRYMedium

Under isothermal condition, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is (Given that 1 L bar = 100 J)

A

-30 J

B

5 kJ

C

25 J

D

30 J

Step-by-Step Solution

Work done Wirr=−PextΔV=−2 bar×(0.25−0.1) L=−2×0.15 L-bar=−0.30 L-bar=−0.30×100 J=−30 JW_{irr} = -P_{ext} \Delta V = -2 \text{ bar} \times (0.25 - 0.1) \text{ L} = -2 \times 0.15 \text{ L-bar} = -0.30 \text{ L-bar} = -0.30 \times 100 \text{ J} = -30 \text{ J}.

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