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NEET CHEMISTRYMedium

CFSE (in the octahedral field) will be maximum in: (Atomic number Co = 27)

A

[Co(H₂O)₆]³⁺

B

[Co(NH₃)₆]³⁺

C

[Co(CN)₆]³⁻

D

[Co(C₂O₄)₃]³⁻

Step-by-Step Solution

Crystal Field Stabilization Energy (CFSE) depends on the magnitude of the crystal field splitting energy (Δo\Delta_o). The value of Δo\Delta_o is directly determined by the field strength of the ligands coordinating to the central metal ion.

  1. Oxidation State: In all the given complexes, Cobalt is in the +3 oxidation state (3d63d^6 configuration).
  2. Spectrochemical Series: According to the spectrochemical series found in the NCERT text, the order of increasing field strength of the ligands involved is: H2O<C2O42<NH3<CNH_2O < C_2O_4^{2-} < NH_3 < CN^-
  3. Conclusion: The cyanide ion (CNCN^-) is the strongest field ligand among the options. It causes the largest splitting of the d-orbitals (maximum Δo\Delta_o). Since CFSE is directly proportional to Δo\Delta_o (specifically for a low-spin d6d^6 complex, CFSE = 2.4Δo-2.4\Delta_o), the complex with the strongest ligand will exhibit the maximum crystal field stabilization energy .
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