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NEET CHEMISTRYMedium

The total number of electrons present in 1.6 g1.6\text{ g} of methane is:

A

6.02×10236.02 \times 10^{23}

B

6.02×10226.02 \times 10^{22}

C

6.02×10216.02 \times 10^{21}

D

4.02×10204.02 \times 10^{20}

Step-by-Step Solution

First, calculate the number of moles of methane (CH4\text{CH}_4). Molar mass of CH4=12+(4×1)=16 g/mol\text{CH}_4 = 12 + (4 \times 1) = 16\text{ g/mol}. Moles of CH4=Given MassMolar mass=1.6 g16 g/mol=0.1 mol\text{CH}_4 = \frac{\text{Given Mass}}{\text{Molar mass}} = \frac{1.6\text{ g}}{16\text{ g/mol}} = 0.1\text{ mol}.

Next, calculate the number of molecules of methane in 0.1 mol0.1\text{ mol}. Number of molecules = Moles×NA=0.1×(6.02×1023)=6.02×1022\text{Moles} \times N_A = 0.1 \times (6.02 \times 10^{23}) = 6.02 \times 10^{22} molecules.

Now, determine the number of electrons in one molecule of CH4\text{CH}_4. A carbon atom (atomic number 6) has 66 electrons, and each hydrogen atom (atomic number 1) has 11 electron. So, one CH4\text{CH}_4 molecule contains 6+4(1)=106 + 4(1) = 10 electrons.

Finally, calculate the total number of electrons in 1.6 g1.6\text{ g} of methane. Total electrons = Number of molecules ×\times Electrons per molecule = (6.02×1022)×10=6.02×1023(6.02 \times 10^{22}) \times 10 = 6.02 \times 10^{23} electrons.

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