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NEET CHEMISTRYEasy

At 27C27^\circ\text{C} latent heat of fusion of a compound is 2930 J/mol2930\text{ J/mol}. Entropy change is:

A

9.77 J/mol K9.77\text{ J/mol K}

B

10.77 J/mol K10.77\text{ J/mol K}

C

9.07 J/mol K9.07\text{ J/mol K}

D

0.977 J/mol K0.977\text{ J/mol K}

Step-by-Step Solution

The entropy change during phase transformation (fusion) is calculated using the formula: ΔSfusion=ΔHfusionTf\Delta S_{\text{fusion}} = \frac{\Delta H_{\text{fusion}}}{T_f} Given: Latent heat of fusion, ΔHfusion=2930 J/mol\Delta H_{\text{fusion}} = 2930\text{ J/mol} Temperature, Tf=27C=27+273=300 KT_f = 27^\circ\text{C} = 27 + 273 = 300\text{ K} Substituting the values into the formula: ΔS=2930 J/mol300 K=9.766 J/mol K9.77 J/mol K\Delta S = \frac{2930\text{ J/mol}}{300\text{ K}} = 9.766\text{ J/mol K} \approx 9.77\text{ J/mol K}

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