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NEET CHEMISTRYEasy

The crystal field stabilization energy (CFSE) for [CoCl6]4[CoCl_6]^{4-} is 18000 cm118000 \text{ cm}^{-1}. The CFSE for [CoCl4]2[CoCl_4]^{2-} will be:

A

6000 cm⁻¹

B

16000 cm⁻¹

C

18000 cm⁻¹

D

8000 cm⁻¹

Step-by-Step Solution

The problem asks for the crystal field splitting energy of a tetrahedral complex (Δt\Delta_t) given the splitting energy of the corresponding octahedral complex (Δo\Delta_o). According to Crystal Field Theory, for the same metal, the same ligands, and similar metal-ligand distances, the relationship between the tetrahedral splitting energy (Δt\Delta_t) and the octahedral splitting energy (Δo\Delta_o) is given by the equation:

Δt=49Δo\Delta_t = \frac{4}{9} \Delta_o

Given that Δo=18000 cm1\Delta_o = 18000 \text{ cm}^{-1} for [CoCl6]4[CoCl_6]^{4-}, we can calculate Δt\Delta_t for [CoCl4]2[CoCl_4]^{2-}:

Δt=49×18000 cm1\Delta_t = \frac{4}{9} \times 18000 \text{ cm}^{-1} Δt=4×2000 cm1\Delta_t = 4 \times 2000 \text{ cm}^{-1} Δt=8000 cm1\Delta_t = 8000 \text{ cm}^{-1}

(Note: While the question uses the term 'CFSE', in this context it refers to the magnitude of the crystal field splitting parameter, Δ\Delta).

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