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NEET CHEMISTRYMedium

For the reversible reaction, N2(g)+3H2(g)2NH3(g)+HeatN_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) + \text{Heat}, the equilibrium shifts in the forward direction:

A

By increasing the concentration of NH3(g)NH_3(g)

B

By decreasing the pressure

C

By decreasing the concentrations of N2(g)N_2(g) and H2(g)H_2(g)

D

By increasing pressure and decreasing temperature

Step-by-Step Solution

According to Le Chatelier's principle, if a system at equilibrium is subjected to a change in temperature, pressure, or concentration, the equilibrium shifts in a direction that counteracts the change.

  1. Temperature: The given reaction is exothermic (heat is released as a product). Lowering the temperature removes heat, which favours the forward (exothermic) reaction.
  2. Pressure: The forward reaction proceeds with a decrease in the number of gaseous moles (1 mol N2+3 mol H2=4 moles1 \text{ mol } N_2 + 3 \text{ mol } H_2 = 4 \text{ moles} on the reactant side; 2 moles NH32 \text{ moles } NH_3 on the product side). Increasing the pressure shifts the equilibrium towards the side with fewer gaseous moles to reduce the pressure, which is the forward direction. Therefore, low temperature and high pressure favour the forward reaction.
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