Back to Directory
NEET CHEMISTRYEasy

For a reaction, activation energy Ea=0E_a = 0 and the rate constant at 200 K200 \text{ K} is 1.6×106 s11.6 \times 10^6 \text{ s}^{-1}. The rate constant at 400 K400 \text{ K} will be [Given that gas constant, R=8.314 J K1 mol1R = 8.314 \text{ J K}^{-1} \text{ mol}^{-1}]

A

3.2×104 s13.2 \times 10^4 \text{ s}^{-1}

B

1.6×106 s11.6 \times 10^6 \text{ s}^{-1}

C

1.6×103 s11.6 \times 10^3 \text{ s}^{-1}

D

3.2×106 s13.2 \times 10^6 \text{ s}^{-1}

Step-by-Step Solution

According to the Arrhenius equation, the relationship between the rate constant (kk) and temperature (TT) at two different temperatures is given by lnk2k1=EaR[1T11T2]\ln \frac{k_2}{k_1} = \frac{E_a}{R} \left[ \frac{1}{T_1} - \frac{1}{T_2} \right] . Given that the activation energy Ea=0E_a = 0, the right side of the equation becomes zero. Therefore, lnk2k1=0\ln \frac{k_2}{k_1} = 0, which implies k2k1=e0=1\frac{k_2}{k_1} = e^0 = 1, or k2=k1k_2 = k_1 . This means the rate constant is completely independent of temperature when the activation energy is zero. Thus, the rate constant at 400 K400 \text{ K} will remain exactly the same as at 200 K200 \text{ K}, which is 1.6×106 s11.6 \times 10^6 \text{ s}^{-1}.

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started