Solved: CHEMISTRY Question for NEET | Sushrut

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NEET CHEMISTRYEasy

Which of the following species has a bond angle of 120 $^\circ$ ?

A

SF $_6$

B

NCl $_3$

C

BCl $_3$

D

PH $_3$

Step-by-Step Solution

Analyze BCl $_3$ : The central Boron atom has 3 valence electrons. It forms 3 sigma bonds with Chlorine atoms and has zero lone pairs. According to VSEPR theory, a molecule with 3 bond pairs and 0 lone pairs (AB $_3$ type) adopts a trigonal planar geometry. The hybridisation is sp $^2$ and the bond angle is exactly 120 $^\circ$ .
Analyze other options:

SF $_6$ : Sulphur is sp $^3$ d $^2$ hybridised with octahedral geometry. Bond angles are 90 $^\circ$ .
NCl $_3$ : Nitrogen is sp $^3$ hybridised with 1 lone pair (Pyramidal geometry). Bond angle is less than 109.5 $^\circ$ .
PH $_3$ : Phosphorus is sp $^3$ hybridised (or unhybridised per Drago's rule) with 1 lone pair. Bond angle is close to 93 $^\circ$ (Pyramidal) .

Conclusion: Only BCl $_3$ has a bond angle of 120 $^\circ$ .

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