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NEET CHEMISTRYMedium

Match the compounds given in Column I with the hybridization and shape given in Column II and mark the correct option.

Column I (A) XeF₆ (B) XeO₃ (C) XeOF₄ (D) XeF₄

Column II (1) Distorted octahedral (2) Square planar (3) Pyramidal (4) Square pyramidal

A

A-1, B-2, C-4, D-3

B

A-4, B-3, C-1, D-2

C

A-4, B-1, C-2, D-3

D

A-1, B-3, C-4, D-2

Step-by-Step Solution

  1. Analyze XeF₆ (A): Xenon (8 valence ee^-) forms 6 bonds with Fluorine. Remaining electrons: 86=28-6=2 (1 Lone Pair). Steric number = 7 (sp3d3sp^3d^3). Structure: Distorted octahedral. Matches (1).
  2. Analyze XeO₃ (B): Xenon forms 3 double bonds with Oxygen (uses 6 ee^-). Remaining: 86=28-6=2 (1 Lone Pair). Steric number = 4 (sp3sp^3). Structure: Pyramidal. Matches (3).
  3. Analyze XeOF₄ (C): Xenon forms 1 double bond with Oxygen and 4 single bonds with Fluorine. Total valence ee^- used: 2(O)+4(F)=62(O) + 4(F) = 6. Remaining: 86=28-6=2 (1 Lone Pair). Steric number = 6 (sp3d2sp^3d^2). Structure: Square pyramidal. Matches (4).
  4. Analyze XeF₄ (D): Xenon forms 4 bonds with Fluorine. Remaining: 84=48-4=4 (2 Lone Pairs). Steric number = 6 (sp3d2sp^3d^2). Structure: Square planar. Matches (2).
  5. Conclusion: The correct sequence is A-1, B-3, C-4, D-2.
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